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PhysicsSound WaveMiscellaneousEasy2 minPYQ_2020

PhysicsEasysingle choice

In the diagram, the intensity of waves arriving at $D$ from two coherent sources $s_{1}$ and $s_{2}$ is $I_{0}$ . The wavelength of the wave is $λ = 4 m$ . Resultant intensity at D will be

Options:

Answer:

Solution:

Path difference

$Δ x = s_{2} D - s_{1} D = 5 - 4 = 1 m$

$∴$ The corresponding phase difference will be

$ϕ = \frac{2 π}{λ} \cdot Δ x = (\frac{2 π}{4}) (1) = \frac{π}{2}$

Using $I = I_{1} + I_{2} + 2 \sqrt{I_{1} I_{2}} cos ϕ$

$I = I_{0} + I_{0} + 2 \sqrt{I_{0} I_{0}} cos \frac{π}{2} = 2 I_{0}$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:Sound WaveSubtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2020

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