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Physics - Sound Wave Question with Solution | TestHub

PhysicsSound WaveMiscellaneousEasy2 minPYQ_2020

PhysicsEasysingle choice

The power of sound from the speaker of radio is $10 W$ . Now, the power of sound from the speaker of the radio is increased to $400 W$ by increasing the volume of the radio. The power increased in $dB$ as compared to original power is nearly

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Answer:

Solution:

$P_{1} = 10 \log |\frac{10}{10^{- 12}}|$

$P_{1} = 130 dB$

$P_{2} = 10 \log |\frac{400}{10^{- 12}}|$

$= 10 \log |4 \times 10^{14}|$

$= 140 + 10 \log 4$

$P_{2} = 146 dB$

$∆ P = (146 - 130) = 16 dB$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:Sound WaveSubtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2020

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