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PhysicsSound WaveMiscellaneousEasy2 minPYQ_2020

PhysicsEasysingle choice

The phase difference between two points separated by $0.8 m$ in a wave of frequency $120 Hz$ is $0.5 π$ . The wave velocity is

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Answer:

Solution:

Here, $f = 120 Hz$ , $x = 0.8 m$ and $ϕ = 0.5 π$ .

From, $ϕ = \frac{2 π}{λ} x$ and $λ = \frac{2 πx}{ϕ} = \frac{2 π \times 0.8}{0.5 π} = 3.2 m$

$v = nλ = 120 \times 3.2 = 384 m s^{- 1}$

Stream:JEESubject:PhysicsTopic:Sound WaveSubtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2020

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