A organ pipe open on both ends in the n th harmonic is in resonance with a source of 1000 Hz . The length of pipe is 16.6 cm and speed of sound in air is 332 m / s . Find the value of n .

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Given that, f = 1000 Hz , v = 332 m / s , l = 16.6 cm = 16.6 × 1 0 − 2 m Frequency in a organ pipe open on both ends, f = 2 l nv ​ or n = v 2 fl ​ or n = 332 2 × 1000 × 16.6 × 1 0 − 2 ​ = 1

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