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Physics - Sound Wave Question with Solution | TestHub

PhysicsSound WaveBeatsMedium2 minPYQ_2017

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When a stretched wire and a tuning fork are sounded together, 5 beats per second are produced, when length of wire is $95 cm$ or $100 cm$ , frequency of the fork is

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Solution:

Let the frequency of tuning fork be $n$ . Suppose $l_{1} = 95 cm$ has frequency $n_{1}$ and $l_{2} = 100 cm$ has frequency $n_{2} (< n_{1})$
Also, $\frac{n _{1}}{n _{2}} = \frac{l _{2}}{l _{1}} = \frac{100}{95}$ $n_{1} = \frac{100}{95} n_{2}$ From eqn. (iii), $\frac{100}{95} n_{2} - n_{2} = 10, n_{2} = 190$ From eqn. (ii), $n = n_{2} + 5 = 190 + 5 = 195 Hz$ .

Stream:AIIMSSubject:PhysicsTopic:Sound WaveSubtopic:Beats

⏱ 2mℹ️ Source: PYQ_2017

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