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Physics - Sound Wave Question with Solution | TestHub

PhysicsSound WaveBeatsHard2 minPYQ_2011

PhysicsHardsingle choice

If man were standing unsymmetrically between parallel cliffs, claps his hands and starts hearing a series of echoes at intervals of $1 s$ . If speed of sound in air is $340 m s^{- 1}$ , the distance between two cliffs would be

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Solution:

Let $x$ be distance of person from one cliff and $y$ be distance of person from $2^{nd}$ cliff. Let $y > x ∴ x x y + y y + x = v \times t_{1} = 340 \times 1 = 340 = 170 m = v \times t_{2} = 340 \times 2 = 680 = 340 m .$ Distance between two cliffs $= x + y = 170 + 340 = 510 m$

Stream:AIIMSSubject:PhysicsTopic:Sound WaveSubtopic:Beats

⏱ 2mℹ️ Source: PYQ_2011

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