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Physics - Sound Wave Question with Solution | TestHub

PhysicsSound WaveStanding waveHard2 minPYQ_2011

PhysicsHardsingle choice

In a resonance tube the first resonance with a tunning fork occurs at $16 cm$ and second at $49 cm .$ If the velocity of sound is $330 m / s$ , the frequency of tunning fork is

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Solution:

For closed pipe $l_{1} = \frac{v}{4 n}$ and $l_{2} = \frac{3 v}{4 n}$ $v n = 2 n (l_{2} - l_{1}) = \frac{v}{2 ( l _{2} - l _{1} )} = \frac{330}{2 \times ( 0.49 - 0.16 )} = 500 Hz$

Stream:MHT_CETSubject:PhysicsTopic:Sound WaveSubtopic:Standing wave

⏱ 2mℹ️ Source: PYQ_2011

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