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PhysicsSHMCalculation of time periodEasy2 minQB
PhysicsEasysingle choice

A highly rigid cubical blockAof small massMand sideLis fixed rigidly on to another cubical blockBof the same dimensions and of low modulus of rigidityηsuch that the lower face ofAcompletely covers the upper face ofB. The lower face ofBis rigidly held on a horizontal surface. A small forceFis applied perpendicular to one of the side faces ofA. After the force is withdrawn, blockAexecutes small oscillations, the time period of which is given by

Options:

Answer:
D
Solution:

Modulus of rigidity, η= F A. θ Here, A= L 2

And

θ = x L

Therefore, restoring force is F=−η Aθ=−ηLx



Or acceleration, a= F M =− ηL M x

Since, a∝x , oscillations are simaple harmonic in nature, time period of which is given by

T=2π | displacement acceleration | =2π | x a | =2π M ηL

Stream:JEESubject:PhysicsTopic:SHMSubtopic:Calculation of time period
⏱ 2mℹ️ Source: QB

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