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PhysicsSHMCalculation of time periodEasy2 minQB

PhysicsEasynumerical

A mass $M$ attached to a spring oscillates with a period of $2 s$ . If the mass is increased by $2 kg$ the period increases by one sec. Find the initial mass $M$ (In $kg$ ) assuming that Hooke’s Law is obeyed.

Answer:

1.60

Solution:

$T = 2 π \sqrt{\frac{M}{K}}$ or $T \propto \sqrt{M}, \frac{T_{2}}{T_{1}} = \sqrt{\frac{M_{2}}{M_{1}}}$

$∴ \frac{3}{2} = \sqrt{\frac{M + 2}{M}}$

Solving this equation we get, $M = 1.6 kg$ .

Stream:JEESubject:PhysicsTopic:SHMSubtopic:Calculation of time period

⏱ 2mℹ️ Source: QB

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