Physics - SHM Question with Solution | TestHub

PhysicsSHMKinematicsEasy2 minQB
PhysicsEasysingle choice

A body executes S.H.M. of period 20 seconds. Its velocity is 5 cm s-1, 2 seconds after it has passed the mean position. Find the amplitude of the bob

cos36°=0.809

Options:

Answer:
C
Solution:

Here, T=20 s

Also, whent=2 s, v=5 cm s-1

Now, v=Aωcos ωt=A×2πTcos2πTt

∴ 5 = A × 2 π 2 0 cos 2 π 2 0 × 2 or A π 1 0 cos π 5 = 5

or  πA10cos 36°=5orπA10×0.8090=5

orA=19.67 cm

 

Stream:JEESubject:PhysicsTopic:SHMSubtopic:Kinematics
⏱ 2mℹ️ Source: QB

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