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Physics - SHM Question with Solution | TestHub

PhysicsSHMEnergyMedium2 minQB

PhysicsMediumnumerical

Passage / Comprehension

2 kg and 3 kg blocks are placed on a smooth horizontal surface and connected by spring which is unstretched initially. The blocks are imparted velocities as shown in the figure.

The maximum energy stored in the spring in the subsequent motion will be $n \times v_{0}^{2}$ find the value of n.

Answer:

15.00

Solution:

At maximum spring compression, both blocks share their centre-of-mass speed.

$v_{C} = \frac{( 2 ) ( - 4 v _{0} ) + ( 3 ) ( v _{0} )}{2 + 3} = - v_{0}$

The decrease in kinetic energy is stored in the spring.

$U_{m a x} = \frac{1}{2} (2) (4 v_{0})^{2} + \frac{1}{2} (3) v_{0}^{2} - \frac{1}{2} (5) v_{0}^{2}$

$U_{m a x} = 15 v_{0}^{2} \Rightarrow n = 15$

Stream:JEESubject:PhysicsTopic:SHMSubtopic:Energy

⏱ 2mℹ️ Source: QB

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