The length of the second's pendulum on the surface of the earth is 1 m . If the acceleration due to gravity on the surface of the moon is one-sixth of the acceleration due to gravity of the earth

Question

The length of the second's pendulum on the surface of the earth is 1 m . If the acceleration due to gravity on the surface of the moon is one-sixth of the acceleration due to gravity of the earth, then the length of the second's pendulum on the surface of the moon will be

TestHub · Accepted Answer

Seconds pendulum is a special pendulum having a time period of $2 s$ .

Using the formula $T = 2 π \sqrt{\frac{L}{g}}$

If the time period remains the same and $g$ is reduced by a factor of $6$ .
L should be reduced by a factor of 6.

$\Rightarrow L = \frac{1}{6} m$ on moon.

Physics - SHM Question with Solution | TestHub

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