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Physics - SHM Question with Solution | TestHub

PhysicsSHMEnergyEasy2 minQB

PhysicsEasysingle choice

A particle starts SHM from the mean position. Its amplitude is $a$ and total energy $E$ . At one instant its kinetic energy is $\frac{3 E}{4}$ . Its displacement at that instant is

Options:

Answer:

Solution:

$K = \frac{1}{2} m ω^{2} (a^{2} - y^{2})$

$\frac{3}{4} E = \frac{1}{2} m ω^{2} (a^{2} - y^{2})$

$\frac{3}{4} (\frac{1}{2} m ω^{2} a^{2}) = \frac{1}{2} m ω^{2} (a^{2} - y^{2})$

$y^{2} = a^{2} - \frac{3}{4} a^{2} = \frac{a^{2}}{4}$

$\Rightarrow$ $y = \frac{a}{2}$

Stream:JEESubject:PhysicsTopic:SHMSubtopic:Energy

⏱ 2mℹ️ Source: QB

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