Physics - SHM Question with Solution | TestHub

Speed is maximum when y = 0

$\therefore \mathrm{ 0}=a\cos \left(\omega t+\frac{\pi }{4}\right)$

$\omega t+\frac{\pi }{4}=\left(2n+1\right)\frac{\pi }{2}$

$\omega t=n\pi +\frac{\pi }{4}$

$t=\frac{n\pi }{\omega }+\frac{\pi }{4\omega }$

for$n=\mathrm{0,}t=\frac{\pi }{4\omega }$