Physics - SHM Question with Solution | TestHub

The phase of a particle in simple harmonic motion is given by $\varphi =\omega t+{\varphi }_0$.

The time period of one complete oscillation is $T=\frac{2\pi }{\omega }$.

For two complete oscillations, the time elapsed is $\Delta t=2T=\frac{4\pi }{\omega }$.

The change in phase is $\Delta \varphi =\omega \Delta t=\omega \left(\frac{4\pi }{\omega }\right)=4\pi$ radians.

Answer: $4\pi$ radian