The phase of a particle performing a linear S.H.M increases by 6 π c after every 5 second. The frequency of its oscillation is

Question

The phase of a particle performing a linear S.H.M increases by 6 π c ​ after every 5 second. The frequency of its oscillation is

TestHub · Accepted Answer

The phase of a particle in S.H.M is given by $ϕ = ω t + ϕ_{0}$

The change in phase over a time interval $Δ t$ is $Δ ϕ = ω Δ t$

Given $Δ ϕ = \frac{π}{6}$ and $Δ t = 5 s$

$ω \times 5 = \frac{π}{6}$

$ω = \frac{π}{30} rad/s$

The frequency of oscillation $f$ is given by $f = \frac{ω}{2 π}$

$f = \frac{π /30}{2 π} = \frac{1}{60} Hz$

Answer: $\frac{1}{60} Hz$

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