Savitha, a XI standard student, while conducting an experiment to determine the effective length of a simple pendulum L, notes down the data of time taken to complete 30 oscillations as 60 s and hence

Question

Savitha, a XI standard student, while conducting an experiment to determine the effective length of a simple pendulum L, notes down the data of time taken to complete $30$ oscillations as $60$ s and hence calculates the length of the simple pendulum as :
(Take $π^{2} = 9.8$ , and $g = 9.8$ m/s $^{2}$ )NEET 2026 (Cancelled)

TestHub · Accepted Answer

Time period T = 30 60 ​ = 2 s. The formula for the time period of a simple pendulum is T = 2 π g L ​ ​ . Squaring both sides, we get T 2 = 4 π 2 g L ​ . Substituting the given values T = 2 s, π 2 = 9.8 , and g = 9.8 m/s 2 : ( 2 ) 2 = 4 × 9.8 × 9.8 L ​ 4 = 4 L L = 1 m. Answer: 1 m

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