Physics - SHM Question with Solution | TestHub

Given $k=180$ N/m, $m=0.2$ kg, and $A=4$ cm $=0.04$ m.

The angular frequency of the spring-mass system is given by:

$\omega =\sqrt{\frac{k}{m}}$

Substituting the given values:

$\omega =\sqrt{\frac{180}{0.2}}=\sqrt{900}=30$ rad/s

The velocity of the mass at the equilibrium position is its maximum velocity, which is given by:

$v_{max}=A\omega$

$v_{max}=0.04\times 30=1.2$ m/s

Answer: $1.2$ m/s