Physics - SHM Question with Solution | TestHub

The path length of oscillation is the total distance between the two extreme positions, which is $2A$.

$2A=8$ cm $\Rightarrow A=4$ cm

The angular frequency of the simple pendulum is given by $\omega =\sqrt{\frac{g}{l}}$

Substituting $g={\pi }^2$ m/s${}^2$ and $l=1$ m:

$\omega =\sqrt{\frac{{\pi }^2}{1}}=\pi$ rad/s

The maximum velocity of the pendulum is given by $v_{\text{max}}=A\omega$

$v_{\text{max}}=4\times \pi =4\pi$ cm/s

Answer: $4\pi$ cm/s