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PhysicsSHMMiscellaneousMedium2 minPYQ_2024

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Let $ω_{1}, ω_{2}$ and $ω_{3}$ be the angular speed of the second hand, minute hand and hour hand of a smoothly running analog clock, respectively. If $x_{1}, x_{2}$ and $x_{3}$ are their respective angular distances in 1 minute then the factor which remains constant $(k)$ isNEET 2024 (Re-NEET)

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$ω_{1} = \frac{2 π}{60}; x_{1} = \frac{2 π}{60} \times 60 = 2 π$ $ω_{2} = \frac{2 π}{3600}; x_{2} = \frac{2 π}{3600} \times 60 = \frac{2 π}{60}$ $ω_{3} = \frac{2 π}{3600 \times 12}; x_{3} = \frac{2 π}{3600 \times 12} \times 60 = \frac{2 π}{720}$ $\frac{ω _{1}}{x _{1}} = \frac{ω _{2}}{x _{2}} = \frac{ω _{3}}{x _{3}} = \frac{1}{60} = k$

Stream:NEETSubject:PhysicsTopic:SHMSubtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2024

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