Physics - SHM Question with Solution | TestHub

The phase of a particle in simple harmonic motion is given by $\varphi =\omega t+{\varphi }_0$.

In one complete oscillation, the time elapsed is $T=\frac{2\pi }{\omega }$.

The change in phase during one oscillation is $\Delta \varphi =\omega T=\omega \left(\frac{2\pi }{\omega }\right)=2\pi$ rad.

For two complete oscillations, the change in phase is $2\times 2\pi =4\pi$ rad.

Answer: $4\pi \mathrm{rad}$.