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Physics - SHM Question with Solution | TestHub

PhysicsSHMEnergyMedium2 minPYQ_2023

PhysicsMediumsingle choice

A particle is vibrating in S.H.M. with an amplitude of $4 cm$ . At what displacement from the equilibrium position is its energy half potential and half kinetic?

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Answer:

Solution:

$K.E P.E ∴ T . E ∴ A^{2} ∴ A^{2} ∴ X ∴ x = \frac{1}{2} m ω^{2} (A^{2} - x^{2}) and = \frac{1}{2} m ω^{2} x^{2} = K \cdot E + P \cdot E = \frac{1}{2} m ω^{2} (A^{2} - x^{2}) + \frac{1}{2} m ω^{2} x^{2} = \frac{1}{2} m ω^{2} A^{2} Given: K \cdot E = P \cdot E, - x^{2} = x^{2} = 2 x^{2} = \frac{A ^{2}}{2} = \frac{A}{2} = \frac{4}{2} = 22 cm$

Stream:MHT_CETSubject:PhysicsTopic:SHMSubtopic:Energy

⏱ 2mℹ️ Source: PYQ_2023

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