The velocity of a particle executing SHM varies with displacement ( $x$ ) as $4 v^{2} = 50 - x^{2}$ . The time period of oscillations is $\frac{x}{7} s$ . The value of $x$ is ______.
[Take $π = \frac{22}{7}$ ]

Question

The velocity of a particle executing SHM varies with displacement ( x ) as 4 v 2 = 50 – x 2 . The time period of oscillations is x 7 s . The value of x is ______. [Take π = 22 7 ]

TestHub · Accepted Answer

Given: 4 v 2 = 50 - x 2 ⇒ v = 1 2 50 - x 2 Comparing with standard equation of SHM, v = ω A 2 - x 2 , we get ω = 1 2 Now, T = 2 π ω = 4 π = 88 7 Hence, required x = 88 .

Physics - SHM Question with Solution | TestHub

Doubts & Discussion