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Physics - SHM Question with Solution | TestHub

PhysicsSHMMiscellaneousEasy2 minPYQ_2022

PhysicsEasysingle choice

Two massless springs with spring constants $2 k$ and $9 k$ , carry $50 g$ and $100 g$ masses at their free ends. These two masses oscillate vertically such that their maximum velocities are equal. Then, the ratio of their respective amplitudes will be :

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Answer:

Solution:

Maximum velocity is given by $v_{\max} = ω A$ $= \sqrt{\frac{k}{m}} A$

Here, $\sqrt{\frac{k_{1}}{m_{1}}} A_{1} = \sqrt{\frac{k_{2}}{m_{2}}} A_{2}$

$\Rightarrow \sqrt{\frac{2 k}{50 \times 10^{- 3}}} A_{1} = \sqrt{\frac{9 k}{100 \times 10^{- 3}}} A_{2}$

$\Rightarrow 2 A_{1} = 3 A_{2}$

Thus, ratio of amplitude is $\frac{A_{1}}{A_{2}} = \frac{3}{2} = 3 : 2$ .

Stream:JEESubject:PhysicsTopic:SHMSubtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2022

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