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PhysicsSHMCalculation of time periodEasy2 minPYQ_2021

PhysicsEasysingle choice

If the time period of a two meter long simple pendulum is $2 s$ , the acceleration due to gravity at the place where pendulum is executing S.H.M. is:

Answer:

Solution:

$T = 2 π \sqrt{\frac{l}{g}}$

$2 = 2 π \sqrt{\frac{2}{g}}$

$\Rightarrow g = 2 π^{2}$

Stream:JEESubject:PhysicsTopic:SHMSubtopic:Calculation of time period

⏱ 2mℹ️ Source: PYQ_2021

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