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PhysicsSHMCalculation of time periodEasy2 minPYQ_2020

PhysicsEasysingle choice

A particle executes $S H M$ along a straight line so that its period is $12 s$ . The time it takes in traversing a distance equal to half its amplitude from its equilibrium position is-

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Answer:

Solution:

for T = 12 s, $ω = \frac{2 π}{T} = \frac{2 π}{12} = \frac{π}{6}$

Using $x = A \sin (ω t)$ (from equilibrium position)

$\frac{A}{2} = A \sin (\frac{π}{6} t)$

$\Rightarrow \frac{π}{6} t = 30 ° = \frac{π}{6}$

$\Rightarrow$ $t = 1 s$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:SHMSubtopic:Calculation of time period

⏱ 2mℹ️ Source: PYQ_2020

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