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PhysicsSHMMiscellaneousEasy2 minPYQ_2020

PhysicsEasysingle choice

If a simple pendulum oscillates with an amplitude of $50 mm$ and time period of $2 s$ , then its maximum velocity is

Answer:

Solution:

$v_{m a x} = a ω = a \times \frac{2 π}{T} = (50 \times 10^{- 3}) \times \frac{2 π}{2} = 0.15 m s^{- 1}$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:SHMSubtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2020

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