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PhysicsSHMMiscellaneousEasy2 minPYQ_2020
PhysicsEasysingle choice

A simple pendulum4 mlong swings with an amplitude of0.2 m. What is its acceleration at the ends of its path ?g=10 m s-2

Options:

Answer:
C
Solution:



T=mgcos⁡θ

∴Fnet=mg sin θ 

and acceleration=gsin⁡θ=gtan⁡θas angle is very smallsin⁡θ=tan⁡θ

∴anet=10×0.24=0.5 m s-2

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:SHMSubtopic:Miscellaneous
⏱ 2mℹ️ Source: PYQ_2020

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