A point mass m = 20 k g , is suspended by a massless spring of constant 2000 N / M . The point mass is released when elongation in the spring is 15 cm. The equation of displacement of particle as a fu

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A point mass m = 20 k g , is suspended by a massless spring of constant 2000 N / M . The point mass is released when elongation in the spring is 15 cm. The equation of displacement of particle as a function of time is (Take g = 10 m / s 2 )

TestHub · Accepted Answer

The motion of block is S.H.M. ∴ y = A sin ⁡ ω t + ϕ Here amplitude is A = m g k = 20 × 10 2000 m = 10 c m At t = 0 , displacement of body with respect to mean position is y = 15 - 10 = 5 c m ∴ 5 = 10 sin ⁡ ω × 0 + ϕ or 1 2 = sin ⁡ ϕ ⇒ ϕ = π 6 ∴ y = 10 sin ⁡ 10 t + π 6

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