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PhysicsSHMCalculation of time periodEasy2 minPYQ_2020

PhysicsEasysingle choice

A particle executing SHM of amplitude $4 cm$ and $T = 4 s$ . The time taken by it to move from positive extreme position to half the amplitude is

Options:

Answer:

Solution:

Equation of motion $y = acos ωt$

$\Rightarrow \frac{a}{2} = acos ωt$

$\Rightarrow \cos ωt = \frac{1}{3}$

$\Rightarrow ωt = \frac{π}{3}$

$\Rightarrow \frac{2 πt}{T} = \frac{π}{3}$

$\Rightarrow t = \frac{\frac{π}{3} \times t}{2 π} = \frac{4}{3 \times 2} = \frac{2}{3} s$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:SHMSubtopic:Calculation of time period

⏱ 2mℹ️ Source: PYQ_2020

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