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Physics - SHM Question with Solution | TestHub

PhysicsSHMMiscellaneousEasy2 minPYQ_2020

PhysicsEasysingle choice

The amplitude of a simple pendulum is $10 cm$ . When the pendulum is at a displacement of $4 cm$ from the mean position, the ratio of kinetic and potential energies at that point is

Options:

Answer:

Solution:

$\frac{K . E}{P . E} = \frac{\frac{1}{2} m w^{2} (A^{2} - x^{2})}{\frac{1}{2} m w^{2} x^{2}}$

$\frac{K . E}{P . E} = \frac{A^{2} - x^{2}}{x^{2}}$

Given $A = 10 cm$ and $x = 4$ cm

$\frac{K E}{P E} = \frac{10^{2} - 4^{2}}{4^{2}} = \frac{84}{16} = \frac{21}{4} = 5.25$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:SHMSubtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2020

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