Physics - SHM Question with Solution | TestHub

$x=(2\times {10}^{-2})\cos \pi t$

Here,$a=2\times {10}^{-2} \mathrm{m}=2 \mathrm{cm}$

At$t=0, x=2 \mathrm{c}\mathrm{m}$,$ie$, the object is at the positive extreme, so to acquire maximum speed (i.e., to reach mean position) it takes$\frac{1}{4}$th of the time period.

$\therefore$Required time =$\frac{T}{4}$

where$\omega =\frac{2\pi }{T}=\pi$

$\Rightarrow T=2 \mathrm{s}$

So, the required time =$\frac{T}{4}=\frac{2}{4}=0.5$s