Physics - SHM Question with Solution | TestHub

Total potential energy$=0.04\mathrm{ }\mathrm{J}$
Resting potential energy$=0.01\mathrm{ }\mathrm{J}$
Maximum kinetic energy$=\left(0.04-0.01\right)$

$=0.03\mathrm{ }\mathrm{J}$
$\therefore 0.03 J=\frac{1}{2} m {\omega }^2 A^2=\frac{1}{2} k{A}^2$

$\therefore 0.03 =\frac{1}{2}\times k\times {\left(\frac{20}{1000}\right)}^2$

$\therefore \mathrm{k}=0.06\times 2500 \mathrm{N} {\mathrm{m}}^{-1}=150 \mathrm{N} {\mathrm{m}}^{-1}$