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PhysicsSHMCalculation of time periodEasy2 minPYQ_2020

PhysicsEasysingle choice

A horizontal platform with an object placed on it is executing $S H M$ in the vertical direction. The amplitude of oscillation is $2.5 c m$ . What must be the least period of these oscillations so that the object is not detached?

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Answer:

Solution:

${mω}^{2} a = mg$ , $ω = \sqrt{\frac{g}{a}}$ , $T = 2 π \sqrt{\frac{a}{g}}$

$T = 2 π \sqrt{\frac{2 .5}{1000}} = \frac{π}{10} s$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:SHMSubtopic:Calculation of time period

⏱ 2mℹ️ Source: PYQ_2020

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