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PhysicsSHMCalculation of time periodEasy2 minPYQ_2020

PhysicsEasysingle choice

The displacement $x$ (in meter) of a particle performing simple harmonic motion is related to time t (in second) as $x = 0.05 c o s (4 π t + \frac{π}{4})$ .The frequency of the motion will be

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Answer:

Solution:

Compare the given equation with the standard form

$y = r \cos [\frac{2 π t}{T} - \frac{2 π x}{λ}]$

Coefficient of $t = \frac{2 π}{T} = 2 π n = 4 π, n = 2 H z$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:SHMSubtopic:Calculation of time period

⏱ 2mℹ️ Source: PYQ_2020

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