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PhysicsSHMMiscellaneousEasy2 minPYQ_2020
PhysicsEasysingle choice

A mass of 2.0 kg is put on a flat pan attached to a vertical spring fixed on the ground as shown in the figure. The mass of the spring and the pan is negligible. When pressed slightly and released the mass executes slightly and released the mass executes a simple harmonic motion. The spring constant is 200 N m-1. What should be the minimum amplitude of the motion, so that the mass gets detached from the pan? (Take g=10 ms-2 )

Options:

Answer:
B
Solution:

Let the minimum amplitude of SHM isa.

Restoring force on spring

F=ka

Restoring force is balanced by weightmgof block. For mass to execute simple harmonic motion of amplitudea.

ka=mg

ora=mgk

Here,m=2 kg, k=200 N m-1, g=10 m s-2

∴a=2×10200=10100m

= 10100×100 cm=10 cm

Hence, minimum amplitude of the motion should be 10 cm, so that the mass gets detached from the pan.

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:SHMSubtopic:Miscellaneous
⏱ 2mℹ️ Source: PYQ_2020

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