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Physics - SHM Question with Solution | TestHub

PhysicsSHMCalculation of time periodEasy2 minPYQ_2020

PhysicsEasysingle choice

A body is executing SHM. When the displacement of the body from the mean position is $4 cm$ and $5 cm$ , the values of the corresponding velocity of the body are $10 cm s^{- 1}$ and $8 cm s^{- 1}$ , respectively. The time period of the body is

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Answer:

Solution:

$10 = ω \sqrt{a^{2} - 16}$ ....(1)

$8 = ω \sqrt{a^{2} - 25}$ .....(2)

${(\frac{5}{4})}^{2} = \frac{a^{2} - 16}{a^{2} - 25}$

or $\frac{25}{16} = \frac{a^{2} - 16}{a^{2} - 25}$

$9 a^{2} = 625 - 256$

$a^{2} = \frac{369}{9} = 41$

from equation (i)

$10 = ω \sqrt{41 - 16} = ω \times 5$

or $ω = 2$

$\frac{2 π}{T} = 2$

or $T = π s e c$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:SHMSubtopic:Calculation of time period

⏱ 2mℹ️ Source: PYQ_2020

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