Physics - SHM Question with Solution | TestHub

Given : Amplitude, a = 0.01 m and frequency,

f = 60 Hz.

Maximum acceleration of the particle

$={\omega }^2\text{a}={\left(2\pi \text{f}\right)}^2\text{.}\text{a}$

$={\left(2\pi \times 60\right)}^2\times \text{0.01}$

$=\text{144 }{\pi }^{\mathrm{2 }}{\text{m/s}}^2$