A particle is executing simple harmonic motion ( S H M ) of amplitude A , along the x -axis, about x = 0 . When its potential Energy P E equal kinetic energy K E , the position of the particle will be

Question

A particle is executing simple harmonic motion ( S H M ) of amplitude A , along the x -axis, about x = 0 . When its potential Energy P E equal kinetic energy K E , the position of the particle will be:

TestHub · Accepted Answer

P E = 1 2 k x 2 & K E = 1 2 K A 2 - x 2 As given in question K E = P E ⇒ 1 2 K A 2 - x 2 = 1 2 K x 2 ⇒ 2 x 2 = A 2 ⇒ x = ± A 2

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