Physics - SHM Question with Solution | TestHub

Acceleration of a particle in S.H.M is given by $a=-{\omega }^{2}X$ Where, x is the displacement from mean position Acceleration will be maximum, When $\mathrm{x}=\mathrm{A}$, where A is amplitude $\begin{array}{rl}\therefore & {\mathrm{a}}_{\max }=-{\omega }^2\mathrm{A}\\ & \left|{\mathrm{a}}_{\max }\right|={\omega }^2\mathrm{A}\end{array}$