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Physics - SHM Question with Solution | TestHub

PhysicsSHMEnergyHard2 minPYQ_2018

PhysicsHardsingle choice

Assertion : In simple harmonic motion, kinetic energy and potential energy become equal when the displacement is $(1/ 2)$ times the amplitude. Reason : In simple harmonic motion, kinetic energy is zero when potential energy is maximum.

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Answer:

Solution:

In simple hermonic motion, if $PE = KE$ $\frac{1}{2} m ω^{2} (x^{2}) = \frac{1}{2} m ω^{2} (A^{2} - x^{2})$ or $x^{2} = A^{2} - x^{2}$ or $x = A / 2$ Also, $PE + KE =$ constant, if $PE$ is maximum then $KE$ is zero.

Stream:AIIMSSubject:PhysicsTopic:SHMSubtopic:Energy

⏱ 2mℹ️ Source: PYQ_2018

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