Start Free Mock LoginAlready registered? Login here

Physics - SHM Question with Solution | TestHub

PhysicsSHMMiscellaneousMedium2 minPYQ_2018

PhysicsMediumsingle choice

A mass is suspended from a vertical spring which is executing S.H.M. of frequency $5 Hz$ . The spring is unstretched at the highest point of oscillation. The maximum speed of the mass is [acceleration due to gravity $g = 10 m s^{- 2}$ ]

Options:

Answer:

Solution:

$T = 2 π \sqrt{\frac{m}{k}}$
$n = \frac{1}{2 π} \sqrt{\frac{k}{m}}$
$25 = \frac{1}{4 π^{2}} \frac{k}{m}$
$k = 100 π^{2} m$
$k A = m g$
$A = \frac{m g}{k}$
$V_{max} = ω A$
$= \frac{2 π}{T} A$
$= 2 π n A$
$= \frac{2 π \times 5 \times m g}{k}$
$V_{max} = \frac{10 π \times m \times 10}{100 π^{2} m} = \frac{1}{π} m s^{- 1}$

Stream:MHT_CETSubject:PhysicsTopic:SHMSubtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2018

Doubts & Discussion

Loading discussions...