Physics - SHM Question with Solution | TestHub

PhysicsSHMCalculation of time periodMedium2 minPYQ_2016
PhysicsMediumsingle choice

The bob of a simple pendulum performs SHM with periodTin air and with periodT1in water. Relation betweenT and T1is (neglect friction due to water, density of the material of the bob is98×103 k g /m3,density of wateris1 g /cc)

Options:

Answer:
A
Solution:

T=2πlgeff
In airgeff=gwhere as in water
geff=gσ-ρσ=9.898×103-10398×103
=9.898-198=9.8×18×89=9.89
∴  T1=2πlgeff=2π9lg
⇒ T 1 = 9 T=3T

Stream:MHT_CETSubject:PhysicsTopic:SHMSubtopic:Calculation of time period
⏱ 2mℹ️ Source: PYQ_2016

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