Physics - SHM Question with Solution | TestHub

We know that Kinetic energy $K=\frac{1}{2}m{u}^2$ where $u=\frac{dy}{dt}=\omega a\cos \omega t$ So. $K=\frac{1}{2}m{\omega }^2{a}^2{\cos }^2\omega t$ Hence, kinetic energy varies periodically with double the frequency of SHM. So, when a particle executing SHM oscillates with a frequency v, then the kinetic energy of particle changes periodically with a frequency of $2v$.