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Physics - SHM Question with Solution | TestHub

PhysicsSHMMiscellaneousMedium2 minPYQ_2013

PhysicsMediumsingle choice

A simple pendulum performs simple harmonic motion about $x = 0$ with an amplitude ' $a$ ' and time period ' $T$ '. The speed of the pendulum at $x = a /2$ will be

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Solution:

As simple pendulum performs simple harmonic motion. $∴$ velocity, $v = ω a^{2} - x^{2}$ At, $x = \frac{a}{2}$ $v = \frac{2 π}{T} a^{2} - (\frac{a}{2})^{2} = \frac{2 π}{T} \frac{3 a ^{2}}{2} = \frac{πa 3}{T}$

Stream:AIIMSSubject:PhysicsTopic:SHMSubtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2013

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