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Physics - SHM Question with Solution | TestHub

PhysicsSHMMiscellaneousMedium2 minPYQ_2011

PhysicsMediumsingle choice

A particle executes a simple harmonic motion of time period $T$ . Find the time taken by the particle to go directly from its mean position to half the amplitude

Options:

Answer:

Solution:

$y = a sin ω t = \frac{a s i n 2 π}{T} t$ At the mean position $y = \frac{a}{2}$ $\frac{a}{2} = \frac{a s i n 2 π t}{T} t = \frac{T}{12}$

Stream:MHT_CETSubject:PhysicsTopic:SHMSubtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2011

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