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PhysicsSHMMiscellaneousEasy2 minPYQ_2011

PhysicsEasysingle choice

The displacement of a particle in S.H.M. varies according to the relation $x = 4 (cos π t + sin π t)$ . The amplitude of the particle is

Answer:

Solution:

Hints: $R sin δ = 4$ $R cos δ = 4$ $R = 42$

Stream:WBJEESubject:PhysicsTopic:SHMSubtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2011

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