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Physics - SHM Question with Solution | TestHub

PhysicsSHMMiscellaneousEasy2 minPYQ_2009

PhysicsEasysingle choice

A simple pendulum performs simple harmonic motion about $x = 0$ with an amplitude a and time period T. The speed of the pendulum at $x = a /2$ will be :NEET 2009 (Mains)

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Answer:

Solution:

$v = ω A^{2} - x^{2}$ $= \frac{2 π}{T} a^{2} - \frac{a ^{2}}{4} = \frac{π a 3}{T}$

Stream:NEETSubject:PhysicsTopic:SHMSubtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2009

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