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Physics - SHM Question with Solution | TestHub

PhysicsSHMMiscellaneousEasy2 minPYQ_2009

PhysicsEasysingle choice

A simple pendulum performs simple harmonic motion about $x = 0$ with an amplitude a and time period $T$ . The speed of the pendulum at $x = \frac{a}{2}$ will beNEET 2009 (Screening)

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Solution:

$v = \frac{d y}{d t} = A ω cos ω t = A ω 1 - sin^{2} ω t = ω A^{2} - y^{2}$ Here, $y = \frac{a}{2}$ $∴ v = ω a^{2} - \frac{a ^{2}}{4} = ω \frac{3 a ^{2}}{4} = \frac{2 π}{T} \frac{a 3}{2} = \frac{π a 3}{T}$

Stream:NEETSubject:PhysicsTopic:SHMSubtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2009

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