Physics - SHM Question with Solution | TestHub

Maximum speed of a particle executing SHM is $u_{\max }=a\omega =a(2\pi n)$ $\Rightarrow n=\frac{u_{\max }}{2\pi a}$ Here, $u_{\max }=31.4\mathrm{cm}/\mathrm{s},a=5\mathrm{cm}$ Substituting the given values, we have $n=\frac{31.4}{2\times 3.14\times 5}=1\mathrm{Hz}$